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// pc1 addresses no array object char *pc1 = 0; // pc2 addresses the null character const char *pc2 = "";

C-style strings generally prove error-prone with the novice C or C++ programmer because of the low-level nature of its representation In the following program sequence, we iterate through a number of typical beginner errors The task of the program is straightforward: compute the length of st Unfortunately, our first attempt is incorrect Do you see the error

#include <iostream> const char *st = "The expense of spirit\n"; int main() { int len = 0; while ( st++ ) ++len; cout len ": " st; return 0;

file:///F|/WinDDK/resources/CPPPrimer/c++primerhtm (93 / 1065) [2001-3-29 11:32:03]

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1 Probabilistic Solution: A packet is rebroadcast with a xed probability In general, this solution is problematic because it does not adapt to the density or loss rates in the network Therefore, it may result in large increases in the overhead when it is not needed (eg, in dense areas and/or when interference is low) This solution is included because it provides a reference point that increases redundancy without using any prediction intelligence 2 Counter-Based Solution: If the node does not hear n other nodes rebroadcast the packet within a certain amount of time, it will rebroadcast it again This solution is attractive because it naturally adapts to the interference level and density of the network In a dense/low-interference area, a number of rebroadcasts is likely to be received after a node rebroadcasts a packet.

This program fails because st is not dereferenced that is,

tests whether or not the address st is 0 and not whether the character that it addresses is null The condition will always evaluate as true, because each iteration of the loop adds 1 to the address in st The program will execute forev2er or until the system stops it A loop such as this is referred to as an infinite loop Our second version of the program corrects this mistake It runs to completion Unfortunately, its output is in error Can you see the mistake we've made this time

n 2 b(j)

#include <iostream> const char *st = "The expense of spirit\n"; int main() { int len = 0; while ( *st++ ) ++len; cout len ": " st endl; return 0; }

The mistake in this case is that st no longer addresses the string literal constant It has been advanced one character beyond the terminating null character (The output of the program depends on the contents of the addressed memory) Here is one possible solution: